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how is 4B00+8D21 = 59521 Multiply the segment value (2B8C) by 16 (since each segment is 64KB and there are 16 bytes per segment) to

image text in transcribedhow is 4B00+8D21 = 59521

Multiply the segment value (2B8C) by 16 (since each segment is 64KB and there are 16 bytes per segment) to get the base address of the segment: 2B8C16=4B000. Add the offset value (8D21) to the base address to get the linear address: 4B000 +8D21=59521

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