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How long would it take to remove the logn smallest elements from a heap that contains n entries, using the removeMin operation? Answer is each
How long would it take to remove the logn smallest elements from a heap that contains n entries, using the removeMin operation?
Answer is each removeMin call runs in O(logn) so logn calls would run on the order of O(logn^2)... why though?
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Spatial Databases With Application To GIS
Authors: Philippe Rigaux, Michel Scholl, Agnès Voisard
1st Edition
1558605886, 978-1558605886
