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How many grams of aluminum sulfate are produced when 75.0 mL of 2.2 M Sulfuric acid are completely neutralized? Al2O3 (s) + 3 H2SO4 (aq)

How many grams of aluminum sulfate are produced when 75.0 mL of 2.2 M Sulfuric acid are completely neutralized?

Al2O3 (s) + 3 H2SO4 (aq) ---> Al2(SO4)3 (aq) +3 H H2O (l)

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