How many ways are there for $10$ women and $6$ men to stand in a line so that no two men stand next to each other? $[$Hint: first position the women and then consider possible positions for men.$]$

$P(16,16)$

$P(16,16)-P(6,6)$

$P(10,10)**P(6,6)$

$P(10,10{)}^{**}P(11,6)$