How much heat is required to convert $56\mathrm{.}52$ grams of C$2$Cl$3$F$3,$ at $760$ mm Hg pressure, from $69\mathrm{.}1$ oC to $35\mathrm{.}92$ oC$?$

Here is your given information:

The compound C$2$Cl$3$F$3$ has a normal B$.$P$.$ of $47\mathrm{.}6$ oC$.$

The specific heat of that compound as a liquid is $0\mathrm{.}910$ J$/($g$*$K$)$ and

The specific heat of that compound as a gas is $0\mathrm{.}670$ J$/($g$*$K$).$

The $\backslash$Delta Hevap of the compound is $27\mathrm{.}49$ kJ$/$mol$.$