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How much thermal energy must be added (in BTU) to 21.4 lb of aluminum in order to get its temperature to change by 28.0 Fahrenheit

How much thermal energy must be added (in BTU) to 21.4 lb of aluminum in order to get its temperature to change by 28.0 Fahrenheit degrees?

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Heat Constants Material Specific Heat Capacity Specific Latent Heat Specific Latent Heat (c) of Fusion (LF) of Vaporization (L.) kJ/kg-Co kcal/kg-Co kcal/kg BTU/lb kcal/kg BTU/b or or J/g-Co BTU/1b-F Air 0.24 51 92 Alcohol 2.40 0.58 25 46 205 369 (ethyl) Aluminum 0.90 0.22 77 139 1990 3591 Brass 0.090 Copper 0.385 0.093 42 76 1750 3158 Glass 0.21 Gold 0.129 0.03 Hydrogen 3.4 108 195 Ice 2.09 0.51 80 144 Iron 0.449 0.12 Lead 0.128 0.032 5.5 9.9 Marble 0.21 Mercury 0.14 0.033 2.8 5.0 71 128 Oxygen 3.2 5.8 50 90 Silver 0.056 Steam 0.48 540 970 Tin 0.0525 Water 4.19 1.00 80 144 540 970 (liquid) Zinc 0.090 28 51 Note: These numbers are for use in solving the problems in this class. It should be noted that different sources will provide slightly different values. It should also be noted that there are 4. 186 Joules in 1 standard calorie

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