How rnu uld their mase snertra he used to distinnu ush hetumpen the fallowinn rnmnnu unde?\ all tnat appiy.\ 4-Heptanone will have a peak at

(m)/(z)=86

due to a McLafferty rearrangement.\ 2-Heptanone will have a peak at

(m)/(z)=58

due to a McLafferty rearrangement.\ 2,4-Dimethyl-3-pentanone does not have any

\\\\gamma

-hydrogens. Therefore, it cannot undergo a McLafferty rearrangement, so it will not have a peak at

(m)/(z)=58

.\ 2-Heptanone will have a base peak at

(m)/(z)=99

, whereas the other two ketones will have base peaks at

(m)/(z)=43

.\ 2,4-Dimethyl-3-pentanone will have a peak at

(m)/(z)=58

due to a McLafferty rearrangement.\ 2,4-Dimethyl-3-pentanone will have a base peak at

(m)/(z)=57

, whereas the other two ketones will have base peaks at

(m)/(z)=43

.\ 2-Heptanone has

\\\\gamma

-hydrogens. Therefore, it cannot undergo a McLafferty rearrangement, so it will not have a peak at

(m)/(z)=58

or at

(m)/(z)=86

.\ Incorrect; Try Again; One attempt remaining

How could their mass spectra be used to distinguish between the following compounds? Check all that apply. 4-Heptanone will have a peak at m/z=86 due to a McLafferty rearrangement. 2-Heptanone will have a peak at m/z=58 due to a McLafferty rearrangement. 2,4-Dimethyl-3-pentanone does not have any -hydrogens. Therefore, it cannot undergo a McLafferty rearrangement, so it will not have a peak at m/z=58. 2-Heptanone will have a base peak at m/z=99, whereas the other two ketones will have base peaks at m/z=43. 4-Heptanone will have a base peak at m/z=71,2-heptanone will have a base peak at m/z=43, and 2,4 -dimethyl-3-pentanone will have a base peak at m/z=71. 2,4-Dimethyl-3-pentanone will have a peak at m/z=58 due to a McLafferty rearrangement. 2,4-Dimethyl-3-pentanone will have a base peak at m/z=57, whereas the other two ketones will have base peaks at m/z=43. 2-Heptanone has -hydrogens. Therefore, it cannot undergo a McLafferty rearrangement, so it will not have a peak at m/z=58 or at m/z=86. Incorrect; Try Again; One attempt remaining How could their mass spectra be used to distinguish between the following compounds? Check all that apply. 4-Heptanone will have a peak at m/z=86 due to a McLafferty rearrangement. 2-Heptanone will have a peak at m/z=58 due to a McLafferty rearrangement. 2,4-Dimethyl-3-pentanone does not have any -hydrogens. Therefore, it cannot undergo a McLafferty rearrangement, so it will not have a peak at m/z=58. 2-Heptanone will have a base peak at m/z=99, whereas the other two ketones will have base peaks at m/z=43. 4-Heptanone will have a base peak at m/z=71,2-heptanone will have a base peak at m/z=43, and 2,4 -dimethyl-3-pentanone will have a base peak at m/z=71. 2,4-Dimethyl-3-pentanone will have a peak at m/z=58 due to a McLafferty rearrangement. 2,4-Dimethyl-3-pentanone will have a base peak at m/z=57, whereas the other two ketones will have base peaks at m/z=43. 2-Heptanone has -hydrogens. Therefore, it cannot undergo a McLafferty rearrangement, so it will not have a peak at m/z=58 or at m/z=86. Incorrect; Try Again; One attempt remaining