how to get the N(0.09739) value in calculator in this problem?

\begin{tabular}{|c|c|c|c|c|c|c|} \hline so & stock price & $40.00 & & T & time to expiration & 0.50 \\ \hlinex & exercise price & $42 & & v= & standard deviation & 0.41 \\ \hline r & risk free interest rate & 7.0% & & & (volatality) & \\ \hline \multicolumn{7}{|c|}{ put price =Xe rt N(d2)S.N(d1)} \\ \hline \multirow[t]{3}{*}{d1=} & ln(SO/X)+(r+(v2/2))T & & & d2= & d1 vT/2 & \\ \hline & VTy/2 & & & & & \\ \hline & & 6.19 & & & & \\ \hline \multirow{2}{*}{d1=} & 0.02823484 & \multirow{2}{*}{=} & \multirow[t]{2}{*}{0.0973905} & \multirow[t]{2}{*}{d2=} & \multirow{2}{*}{t0.192523322} & \\ \hline & 0.28991378 & & & & & \\ \hline \multirow[t]{3}{*}{N(d1)} & N(0.09739) & = & 0.4612082 & N(d2) & N(0.192523)= & 0.5763338 \\ \hline & & & & & & \\ \hline & & & & & \pm & \\ \hline \multicolumn{2}{|c|}{ value of the option put =} & \multicolumn{3}{|c|}{XertN(d2)S.N(d1)} & & \\ \hline & = & 23.3735 & - & 18.44833 & & \\ \hline & & $4.93 & & & & \\ \hline & & & & & & \\ \hline & & & & & & \\ \hline \end{tabular}