how to solve this?

Substitute x= 12,755, u =12,752, o=2.4, and n = 33 into the formula for z and simplify. x - U Z = o/ vn 12,755 - 12,752 2.4/ 133 = 7.18 (Round to two decimal places as needed.) So, the probability that the sample mean is greater than 12,755 is equal to P (x > 12,755) = P(z > 7.18). This probability corresponds to the area to the right of z = 7.18 under the Standard Normal Distribution. To find the area to the right of z, first use technology to find the area to the left of z. Then subtract the area from 1. Note that either technology or a Standard Normal Table can be used to find this area, but in this problem we will use technology. What is the area that corresponds to z = 7.18? (Round to three decimal places as needed.)