how to solve this with step by step. with correct length and

Learning Goal: Part B To practice Tactics Box 3.2 Finding the acceleration vector. Suppose an object has an initial velocity vi at time ti and Below is another motion diagram for an object that moves along a curved path. The dots represent the position of the object at five subsequent instants, t1, t2, t3, ta, and ts. The vectors v21, 232, 143, and later, at time tr, has velocity ur. The fact that the velocity represent the average velocity of the object during the four corresponding time intervals. Draw the acceleration vectors a3, and ass representing the changes in velocity of the object during the time interva changes tells us the object undergoes an acceleration At31 = t3 - t1 and Ats3 = ts - t3, respectively. during the time interval At = tf - ti. From the definition of acceleration, Draw the vectors starting at the appropriate black dots. The location, orientation, and length of the vectors will be graded. >View Available Hint(s) a Au If ti At we see that the acceleration vector points in the same direction as the vector Avi. This vector is the change in the + velocity Av = of - vi, so to know which way the acceleration vector points, we have to perform the vector subtraction of - vi. This Tactics Box shows how to use -121 Vector opposite to v21 vector subtraction to find the acceleration vector. -143 Vector opposite to v43 a31 acceleration between times 1 and 3 as3 Acceleration between times 3 and 5 121 Figure