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Hugo averages 43 words per minute on a typing test with a standard deviation of 12.5 words per minute. Suppose Hugo's words per minute on

Hugo averages 43 words per minute on a typing test with a standard deviation of 12.5 words per minute. Suppose Hugo's words per minute on a typing test are normally distributed. Let X= the number of words per minute on a typing test. Then, XN(43,12.5). Suppose Hugo types 76 words per minute in a typing test on Wednesday. The z-score when x=76 is ________. This z-score tells you that x=76 is ________ standard deviations to the ________ (right/left) of the mean, ________. Correctly fill in the blanks in the statement above.

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Suppose Hugo types 76 words per minute in a typing test on Wednesday. The z-score when x=76 is 2.64. This z-score tells you that x=76 is 2.64 standard deviations to theleftof the mean, 43.

Suppose Hugo types 76 words per minute in a typing test on Wednesday. The z-score when x=76 is 2.129. This z-score tells you that x=76 is 2.129 standard deviations to therightof the mean, 43.

Suppose Hugo types 76 words per minute in a typing test on Wednesday. The z-score when x=76 is 2.129. This z-score tells you that x=76 is 2.129 standard deviations to theleftof the mean, 43.

Suppose Hugo types 76 words per minute in a typing test on Wednesday. The z-score when x=76 is 2.64. This z-score tells you that x=76 is 2.64 standard deviations to therightof the mean, 43.

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