Hugo averages 53 words per minute on a typing test with a standard deviation of 9 words per minute. Suppose Hugo's words per minute on a typing test are normally distributed. Let X= the number of words per minute on a typing test. Then, XN(53,9). Suppose Hugo types 61 words per minute in a typing test on Wednesday. The z-score when x=61 is ________. This z-score tells you that x=61 is ________ standard deviations to the ________ (right/left) of the mean, ________. Correctly fill in the blanks in the statement above.

A) Suppose Hugo types 61 words per minute in a typing test on Wednesday. The z-score when x=61 is 0.889. This z-score tells you that x=61 is 0.889 standard deviations to theleftof the mean, 53.

B) Suppose Hugo types 61 words per minute in a typing test on Wednesday. The z-score when x=61 is 0.667. This z-score tells you that x=61 is 0.667 standard deviations to theleftof the mean, 53.

C) Suppose Hugo types 61 words per minute in a typing test on Wednesday. The z-score when x=61 is 0.889. This z-score tells you that x=61 is 0.889 standard deviations to therightof the mean, 53.

D) Suppose Hugo types 61 words per minute in a typing test on Wednesday. The z-score when x=61 is 0.667. This z-score tells you that x=61 is 0.667 standard deviations to therightof the mean, 53.