HW6.6. Finding a basis of the orthogonal complement Consider the matrix 2 0 2 1 0 0 1 A = 1 0 0 1 1 1 0 1 0 0 1 Find a basis for the orthogonal complement to the column space of A. Basis matrix (2 digits after decimal} 0 How to enter the solution: To enter your solution, place the entries of each vector inside of brackets, each entry separated by a comma. Then put all these inside brackets, again separated by a comma. Suppose 1 2 . . 2 3 your solutions IS 1 , 0 .Then please enter 0 1 [[13 2: _12 0]1[2:32 011]] " we Bnow that orthogonal Complement of column space f 4. Pago No. ! i's null space of (AT ) Dato : wehave 1 0 0-1 - I. O O T A 0 O O - 0 - 1 Adding R , ) Ry t R , ucger! 0 0 -10 O O Applying Ro J R g PR , weger O Applying Ry Ry - Rg . A od 1 0 O Applying Ro - - Re veget A = 10 00 0 odood NOW A x = 0 ng O 1 0 0 0 0 2 3 OPage No. : , = 0 Date : 14 = 0 3 let do -t ( free variable) ( free variable ) HeAce (D) becomes a g = t + 8 So general Solution is that forms basis is O [ d, g n a, a g , dy , 2 5 J = [ 0 , t , 8 , 0, - 1 18 So basis , 5 / o, 1 0, 0, - If, 50 2 1,0