Hypothesis Test for the Difference in Two Proportions

You wish to test the following claim $($

$)$ at a significance level of

$.$

You obtain $71\mathrm{.}5\%$ successes in a sample of size

from the first population. You obtain $59\mathrm{.}1\%$ successes in a sample of size

from the second population.

What is the test statistic for this sample? $($Report answer accurate to three decimal places.$)$

test statistic $=$

What is the p$-$value for this sample? $($Report answer accurate to four decimal places.$)$

p$-$value $=$

The p$-$value is$...$

less than $($or equal to$)$

greater than

This test statistic leads to a decision to$...$

reject the null

accept the null

fail to reject the null

As such, the final conclusion is that...

There is sufficient evidence to warrant rejection of the claim that the first population proportion is not equal to the second population proprtion.

There is not sufficient evidence to warrant rejection of the claim that the first population proportion is not equal to the second population proprtion.

The sample data support the claim that the first population proportion is not equal to the second population proprtion.

There is not sufficient sample evidence to support the claim that the first population proportion is not equal to the second population proprtion.