hypothetical scenario: Pretend you are an industrial psychologist consulting with a chain of music stores and you know that the average number of complaints management receives each month throughout the industry is 6.5, but the variance is unknown. Seven of the chain's stores randomly selected to record complaints received for one month: 4, 8, 9, 0, 3, 5, and 6 complaints. Using the .05 significance level, is the number of complaints received by the chain different from the number of complaints received by music stores in general? run a one-sample t-test on the data.A summary of the image analyses according to the hypothetical scenario, include the following:* Explanation of what the study was about * Report the results of the t-test* Give thoughts about this analyses.

T-Test [DataSet] ] One-Sample Statistics N Mean Std. Deviation Std. Error Mean record 7 5.00 3.055 1.155 One-Sample Test Test Value = 6.5 95% Confidence Interval of the Significance Mean Difference t df One-Sided p Two-Sided p Difference Lower Upper record -1.299 6 .121 .242 -1.500 -4.33 1.33 One-Sample Effect Sizes 95% Confidence Interval Standardizer Point Estimate Lower Upper record Cohen's d 3.055 -.491 -1.263 315 Hedges' correction 3.517 -.426 -1.097 .274 a. The denominator used in estimating the effect sizes. Cohen's d uses the sample standard deviation. Hedges' correction uses the sample standard deviation, plus a correction factor