I 1. Twelve orange pulp silage samples were divided at random into four groups of three. One group was left as an untreated control While . . other three groups were treated with formic acid, beet pulp, and sodium chloride, reapectively. The observed moisture content of the silage samples are shown below. Sodium chloride Formic acid Beet pulp Control 80.5 89.1 77.8 76.7 79.3 _ 75.7 79.5 77.2 79.0 81.2 77.0 78.6 M (a) Obtain an analysis of variance table for the data and test the null hypothesis that all four treatments yield the same true average moisture content. Use oz : 0.05. (b) Compute a 99% condence interval for the difference in response between the average of the three treatment groups (acid, pulp, and salt) and the control group. (c) "Compute 95% simultaneous condence intervals for the differences in response between each of the three treatment groups versus the control group. Use the method among Bonferroni, Tukey, and Scheff, that give the shortest intervals