I am confused on how to solve this...

The sixth step in glycolysis is the phosphorylation coupled to oxidation of glyceraldehyde-3-phosphate:

glyceraldehyde-3-phosphate + NAD⁺ + phosphate <-> 1,3-bisphosphglycerate + NADH + H⁺

What is the G (in units of kJ * Mol^-1) for this reaction at human body temperature given the following parameters?

gas constant (R) = 0.008314 kJ * Mol^-1 * K^-1

body temperature = 37^oC (310.16K)

pH = 7

G^o = 6.3 kJ * mol^-1

[1,3-bisphosphoglycerate] = 3.0 * 10^-5 M

[glyceraldehyde-3-phosphate] = 7.0 * 10^-5 M

[NAD⁺] = 3.0 * 10^-4 M

[NADH] = 4.29 * 10^-7 M

[phosphate] = 8.0 * 10^-3 M