i don't know how to derive the equation (22) to (23) or (24).

explain the details of process deriving equations.

All trimolecular reactions found so far are of the form of Eq. 22 or 25. Thus dCA A + 2B R with -PA = =kCACB (22) dt In terms of conversions the rate of reaction becomes dX = kC0 (1 - XAM - 2x.)2 dt = 0 where M = CBO C 20. On integration this gives A0 (2CA0 CBo)(CBo Cb) + In CBOCB CACBO (2CA0 Cbo){kt, M2 (23) or 1 1 , - 8kt, M= 2 (24)