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I dont understand how to find the alpha and beta Consider the following difference equation 33t+1 = 19'th (4 13:) where c > 0 is

I dont understand how to find the alpha and beta

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Consider the following difference equation 33t+1 = 19'th (4 13:) where c > 0 is a parameter. The equation has two equilibria that one is 3:1 : 0. The second one is $2 :- The second equilibrium is stable for c E (or, ,8) where a : S and ,6 : IS Your last answer was interpreted as follows: 4__ C The variables found in your answer were: [0]

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