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I don't understand this f (x) = 8x - 3 and f'(-2) = -2 and f(-2) = -3. Find f(x) 6 cos (6x) X and

I don't understand this

f" (x) = 8x - 3 and f'(-2) = -2 and f(-2) = -3. Find f(x) 6 cos (6x) X and find f(1) = sin (6(-3)) -6(-3) -2 X

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