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I got to the step C=14log 2 (6.50) I can't figure out the next step to get the solution The Shannon-Hartley Law states that the

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I got to the step C=14log2(6.50) I can't figure out the next step to get the solution

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The Shannon-Hartley Law states that the channel capacity C (in Mbit/s) at which information can be transmitted over a communication channel is given by C = Blog 2 1 + where B is the bandwidth (in MHz) and ~ is the signal-to-noise ratio. Find the channel capacity of a 14.0-MHz channel with a signal-to-noise ratio of 5.50. The channel capacity is Mbit/s. (Type your answer using the appropriate number of significant digits.)

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