(I H 0.368 q,- __ | + t 8 'T Figure 4 Figure 5 In this experiment we will determine the time that it takes for the capacitor to charge and discharge to some value. From qn (2) we see that since the capacitance 'C' is constant for a given capacitor, the charge 'Q' is proportional to the voltage 'V' across the capacitor. So, instead of measuring the charge, we will measure the voltage across the capacitor, which will be indicative of the charge. Then the charge will be 4(3) = C A Va\") {5) Where A VCU) is the voltage drop across the capacitor at time t. While charging, when the potential difference across the capacitor reaches the battery potential, the capacitor is fully charged. At that point, the potential drop across the resistor is zero and there is no current in the circuit. PROCEDURE 1. Open the simulation by ctrl+click the link, or copy paste the link to the browser. The simulation should look like that shown in Fig.6 2. Since this simulation is in java [and not web based as some of the others}, you may have to download the simulation. If you cannot run the simulation, you may need to follow the following PhET help guidelines: https:thet.colorado.edufenfhelpcenten'runningsims Then click "Why can I run some of the simulations but not all?\" 3. Run the simulation, and you will see a page like that shown in Fig.7. 4. You would now set up the circuit. For assistance in setting up the circuit, see the manual on Ohm's Law or Kirchhoff's Rules. 5. This experiment requires you to measure the voltage as a function of time. The timer can be easily controlled by using the PausefPlay button {b} andfor the step button { | b} (these are at the bottom of the page). Circuit Ca nstmction Kit [AC+DC}. Virtual Lab \"at-h mm a New! Java Vii Greer\": Choci to m :l 3 WHEN! version mists Figure 6. Figure 7. Case-A: charging the capacitor. 1. Set up the circuit as shown in figure 8. Once set up, it should look something like that shown in figure 9. Set the resistance to 100 Q, capacitance to 0.05 F, and Battery to 10.0 V. Before charging the capacitor, make sure that it has no charge [the voltmeter reads zero}. Otherwise you need to discharge the capacitor first until the voltage across the capacitor becomes zero. Put switch 31 in the ON state and switch 32 to the OFF state. Set the Pausex'Play button [>) to pause and the timer to zero. Before 5 seconds, use the step button { | >} to increase time by 0.5 second intervals and record the voltage values in Table |. After 5 seconds, use the PauselPlay button [>ll | J to record the voltage at around 7.00. 10.0, 15.0, 20.0, and 25.0 seconds. Using equation {5}, obtain the charge at each time, and enter in Table 1. Draw a graph between charge on yaxis and time on xaxis. It should look like Fig. 3. Use the known values of resistance and capacitance to calculate the time constant and the maximum charge by using gm. [2) and eqn. {3}, and enter in Table 2. Calculate the charges equal to one time constant, two time constants, and five time constants and enter in Table 2. Compare these with the experimental values using % error. Put your calculation in the table II. Figure 8 Iu Figure 9. Case-B: Discharging capacitor 1. 2. 3. Set up the circuit as shown in figure 8. Set the resistance to 100 Q, capacitance to 0.05 F, and Battery to 10.0 V. Before discharging the capacitor, make sure the capacitor has been fully charged [the voltmeter reading is very close to 10.0 V). Set switch Sl to off and switch 52 to on. Set the Pausex'Play button [>1 to pause, and the stopwatch to zero. For time less than 5 seconds, use the step button { | >) to increase time by 0.5 second intervals. Record the voltage values in Table 3. After 5 seconds, use the PauselPlay button (>ll l) to record the voltage at about 10.0, 15.0, 20.0, and 25.0 seconds. Using equation {5}, obtain the charge at each time, and enter in Table 3. Draw a graph beTween charge on yaxis and Time on xaxis. IT should look like Fig. 5. Use The known values of resisTance and capaciTance To calculaTe The Time consTanT and The maximum charge by using em. (2) and em. {3}, and enfer in Table 4. Calculafe The charges equal To one Time consTanT, Two Time consTanTs, and five Time consTanTs and enTer in Table 4. Compare These wiTh The experimenTal values using % error. PuT your calculaTion in The Table II. Case-C: Capacllors in Series. l. 2. 3. Sef up The circuiT as shown in figure 10. Sef The resisTance To 100 0, each capaciTance To 0.05 F, and Baffery To 10.0 V. Before charging The capaciTor, make sure ThaT iT has no charge [The voleeTer reads zero}. OTherwise you need To discharge The capaciTor firsT unTil The volTage across The capacifor becomes zero. Puf swiTch S] in The ON sTaTe and swiTch 52 To The OFF sTaTe. Now calculaTe The value of The Time consTanT by using The equaTion for sum of capaciTors in series. STarT charging The capaciTors and noTe The volTage difference across boTh capaciTors. Nofe The Time if Takes for The volTage To reach 63.2 % of Mm. This is The measured value of Time consTanT. NoTe This in Table 5. Now charge The capaciTors To full charge, and by using proper swifching, measure The Time for The volTage across Them To fall BY 63.2% of me- This is The measured Time consTanT for discharging The capaciTors. Compare The measured and calculaTed values of The Time consTanT for capaciTors in series. Figure l T Figure 10 Case-D: Capacitors in parallel. l. 2. 3. 4. Sef up The circuiT as shown in figure ll . SeT The resisTance To 100 Q, each capaciTance To 0.05 F, and Baffery To 10.0 V. RepeaT The sTeps needed To measure The Time consTanT while charging and while discharging, and compare wiTh The calculaTed value for capaciTors in parallel. EnTer The resulTs in Table 5. DATA Case-A: Data for charging a single capacitor Table-1 Resistance R = Capacitance C = Charge Charge Charge Time Measured on Time Measured on Time Measured on Voltage Capacitor (s) Voltage Capacitor Voltage Capacitor (s) (Vc) g(t (Vc) g(t) (s) (Vc) g(t eqn. (5) (eqn. (5) lean. (5) 0.50 3.00 7.00 1.00 3.50 10.0 1.50 4.00 15.0 2.00 4.50 20.0 2.50 5.00 25.0 Make a graph between q(1) and time. Table 2 Maximum Charge from ean (2) = Q = RC time constant from ean (3) = 1 = Calculated value Experimental value error eqn (1) ean (5) Charge at t = 1 t Charge at t = 2 t Charge at t = 3 tCase-B: Data for Discharging a single capacitor Table-3 Resistance R = Capacitance C = Charge Charge Charge Measured on Measured on Measured on Time Capacitor Time Capacitor Time Voltage Capacitor (s) Voltage (Vc) (s) Voltage (s) q(t) (Vc) q (t) (Vc) q(t) lean. (5) eqn. (5) (eqn. (5) 0.50 3.00 7.00 1.00 3.50 10.0 1.50 4.00 15.0 2.00 4.50 20.0 2.50 5.00 25.0 Make a graph between q(t) and time. Table 4 Maximum Charge from ean (2) = Q = RC time constant from ean (3) = 1 = Calculated value Experimental value % error eqn (4) ean (5) Charge at t = 1 t Charge at t = 2 t Charge at t = 3 tCase C and D: Data for Two Capacitors in Series and Parallel: Table 5: Resistance: Capacitance 1: Capacitance 2: Percent Type of Circuit Calculated Measured Measured Percent values of Charging Discharging error in time error in time Capacitors in: of To and to time to time TD of charging discharging Series Parallel to : Time constant for charging TD : Time constant for dischargingTHEORY An RC circuit is one in which we have a resistor in series with a capacitor {Figure i}. In this figure, the battery is not connected to the circuit, and there is no charging of the capacitor. Assume that the capacitor is initially completely uncharged {which can be done by connecting both ends of the capacitor with a piece of wire}. The switch is then thrown to position 'a' at time t = 0 5 {figure 2}. This starts charging the capacitor, and the rate of charging is given by: q0)= Q(1e' in Where .30) is the charge at time t after charging starts, R and C are the values of the resistance and capacitance. Q is the maximum charge that can be stored on the capacitor, and is given by Q=CA% m r=RC {3} Where C is the Capacitance of the capacitor, and A Vis the applied potential across the capacitor {= 3 volts}. The term RC is called the time constant { r} of the RC circuit, and is the time taken for the capacitor to charge to 63.2% of its maximum possible value. (f r: I I: h' l 8 Figure 1 Figure 2 Figure 3 (38 0.632(T8 The capacitor charges with time as shown in Figure 3. Even though equation {1} and this curve indicate that the capacitor will never be fully charged, for most practical purposes we consider that the capacitor is fully charges after a time that is more than 5 timeconstants have passed. To discharge the capacitor through the resistor. we move the switch to position 'b', as in Figure 4. The capacitor discharges according to equation {3}. The charge decreases exponentially as shown in Figure 5. qa)= Qe'? {M