I have a problem I have to solve with c++ and I need help please. The question is : Computers are frequently employed in check-writing systems such as payroll and accounts payable applications. Write a program that inputs a numeric check amount (an integer between 0 and 4 billion) and writes the word equivalent of the amount. For example, the amount 221 should be written as: TWO HUNDRED TWENTY ONE DOLLARS. 1005021 should be written as: ONE MILLION FIVE THOUSAND and TWENTY ONE DOLLARS. My code doesn't work 100%. The second number section doesn't produce anything. For example, 25 comes out as five. Also anything past 1000 doesn't work either. Can some one help? Here is my code:

#include "stdafx.h"

#include

#include

using namespace std;

int reverse(int v, int lim)

{

if (lim == 1)

return v;

else

return (((v % 10)*pow(10, lim - 1)) + reverse(v / 10, lim - 1));

}

void print_c(int digit, int l, int r = 12)

{

if (l != 2)

{

switch (digit)

{

case 1: cout << "One";

break;

case 2: cout << "Two";

break;

case 3: cout << "Three";

break;

case 4: cout << "Four";

break;

case 5: cout << "Five";

break;

case 6: cout << "Six";

break;

case 7: cout << "Seven";

break;

case 8: cout << "Eight";

break;

case 9: cout << "Nine";

break;

}

}

else if (l == 2)

{

switch (digit)

{

case 1: switch (r)

{

case 10: cout << "Ten";

break;

case 11: cout << "Eleven";

break;

case 12: cout << "Twelve";

break;

case 13: cout << "Thirteen";

break;

case 14: cout << "Forteen";

break;

case 15: cout << "Fifteen";

break;

case 16: cout << "Sixteen";

break;

case 17: cout << "Seventeen";

break;

case 18: cout << "Eighteen";

break;

case 19: cout << "Nineteen";

break;

}

break;

case 20: cout << "Twenty";

break;

case 30: cout << "Thirty";

break;

case 40: cout << "Forty";

break;

case 50: cout << "Fifty";

break;

case 60: cout << "Sixty";

break;

case 70: cout << "Seventy";

break;

case 80: cout << "Eighty";

break;

case 90: cout << "Ninty";

break;

case 0: cout << " ";

break;

}

}

}

int main()

{

int num, temp, length = 0, result, n, m = 0;

cout << " Enter the number" << endl;

cin >> num;

temp = num;

for (;num > 0; num /= 10)

{

length++;

}

result = reverse(temp, length);

while (result)

{

n = result % 10;

m = m * 10 + n;

result /= 10;

if (length == 1)

{

print_c(n, length);

}

else if (length == 2)

{

if (n == 1)

{

print_c(n, length, result);

break;

}

else

{

print_c(n, length);

length--;

}

}

else if (length == 3)

{

print_c(n, length);

length--;

if (n != 0)

{

cout << "hundred";

}

}

else if (length == 4)

{

print_c(n, length);

length--;

cout << "Thousand";

}

else if (length == 7)

{

print_c(n, length);

length--;

cout << "Million";

}

else if (length == 13)

{

print_c(n, length);

length--;

cout << "Billion";

}

}

system("pause");

return 0;

}