I have an ironpython script which opens an xaml file containing $2$ tabs$.$ Inside of the first tab there is a listbox and there is a button called "Modify" underneath. How can I make it so that I can open another xaml file which contains some information about the class I selected in the listbox $($Let$\text{'}$s assume it has the class properties: Views, Options, Materials, Objects, Name$).$ To give some more context, I will provide some code I made in IronPython to load the xaml file. class ViewModel$($my$\_$WPF$)$:

context$\_$mode $=$ 'show'

view$\_$mode $=$ 'singular'

context$\_$transp $=0$

context$\_$color $=$ Color$(255,255,255)$

warning$\_$color $=$ Color$(255,0,0)$

count$\_$views$\_$total $=1$

count$\_$view$\_$current $=1$

def $\_\_$init$\_\_($self$)$:

path$\_$xaml$\_$file $=$ xaml$\_$path

wpf$.$LoadComponent$($self$,$ path$\_$xaml$\_$file$)$and later on for the main I have this: if $\_\_$name$\_\_==\text{'}\_\_$main$\_\_\text{'}$:

x $=$ ViewModel$()$

x$.$show$\_$window$()$ the wpf mentioned here just comes from ironpython doing import wpf$.$ Is this possible with XAML and IronPython? If you can give it in either ironpython or C# its fine because I can easily convert these two languages.