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Acne is one of the most common skin conditions in the United States and is estimated to affect 82% of teenagers. A research from the Johns Hopkins Medical School collects a random sample of 225 individuals over the age of 20 and asks them if they suffered from acne in their adolescent years (between the age of 10 and 19). The researcher found that 179 individuals in his or her sample had acne at some point in their adolescent years. What proportion of the sample would be expected to have had acne in their adolescent years? 179 O E = 0.796 Q) 0.82 Acne is one of the most common skin conditions in the United States and is estimated to affect 82% of teenagers. A research from the Johns Hopkins Medical School collects a random sample of 225 individuals over the age of 20 and asks them if they suffered from acne in their adolescent years (between the age of 10 and 19). The researcher found that 179 individuals in his or her sample had acne at some point in their adolescent years. What is the sampling distribution of the sample proportion of individuals who had acne in their adolescent years? 0 13 ~ Binomia1(225,0.82) O 15 ~ AN(0.796, 1/ W = 0.0269) G) 0.82(0.18) 15 ~ AN(0.82, 225 = 0.0256) Acne is one of the most common skin conditions in the United States and is estimated to affect 82% of teenagers. A research from the Johns Hopkins Medical School collects a random sample of 225 individuals over the age of 20 and asks them if they suffered from acne in their adolescent years {between the age of 10 and 19). The researcher found that 179 individuals in his or her sample had acne at some point in their adolescent years. What is the distribution of the following? 0.7960.82 X = 0.32(o.13) 225 O X follows a standard normal distribution. Q) X follows an approximate normal distribution with the same mean and standard deviation as that of the sample proportion, 13. O X follows a t distribution with 224 degrees of freedom. Acne is one of the most common skin conditions in the United States and is estimated to affect 82% of adolescents. A research from the Johns Hopkins Medical School collects a random sample of 225 individuals over the age of 20 and asks them if they suffered from acne in their adolescent years (between the age of 10 and 19). The researcher found that 17 9 individuals in his or her sample had acne at some point in their adolescent years. What is the probability that more 83% of our sampled individuals had acne in their adolescent years? 0 pnorm(0.83, 0.796, 00269) = 0.897 O 1-pnorm(0.83, 0.796, 0.0269) = 0.103 1-pnorm(0.83, 0.82, 0.0256) = 0.348 O pnorm(0.83, 0.82, 0.0256) = 0.651 Acne is one of the most common skin conditions in the United States and is estimated to affect 82% of adolescents. A research from the Johns Hopkins Medical School collects a random sample of 225 individuals over the age of 20 and asks them if they suffered from acne in their adolescent years (between the age of 10 and 1 9). The researcher found that 1 79 individuals in his or her sample had acne at some point in their adolescent years. What is the standard error for the sample proportion of individual who had acne in their adolescent years? 0 U.82(0.18) _ 1/225 _ 0.0256 0.796(0.204) 225 O 1/0.796(0.204.) = 0.403 O 1/0.82(0.18) = 0.384 = 0.0269 According the American Heart Association, 48% of all Americans in the United States have some type of cardiovascular disease. They claim that 6.3% of women and 11.2% of males have some type of cardiovascular disease. A random sample of 200 women and 150 men were assessed for signs of cardiovascular disease. What is the expected difference between the proportions of cardiovascular disease comparing men to women? 0.049 O The difference between the sample proportions of cardiovascular disease of males and females (151 Zia )- According the American Heart Association, 48% of all Americans in the United States have some type of cardiovascular disease. They claim that 6.3% of women and 11.2% of males have some type of cardiovascular disease. A random sample of 200 women and 150 men were assessed for signs of cardiovascular disease. Based on the information, can we nd the standard deviation of the difference between the sample proportions? Q We cannot nd the standard deviation. g Y .t. 0.063(0.937) 0.112(0.888) _ _ es,| IS TO + T 0.031 0 Yes, it is 0.063(0.937) 0.112(0.888) 150 + 200 = 0'029' According the American Heart Association, 48% of all Americans in the United States have some type of cardiovascular disease. They claim that 6.3% of women and 11.2% of males have some type of cardiovascular disease. A random sample of 200 women and 150 men were assessed for signs of cardiovascular disease. Based on the information, can we find the standard error of the difference between the sample proportions? O Yes, it is 0.063 (0.937) 0.112(0.888) 150 200 = 0.029 We cannot find the standard error. O Yes, it is 0.063(0.937) + 0.112(0.888) 200 150 = 0.031 .According the American Heart Association, 48% of all Americans in the United States have some type of cardiovascular disease. They claim that 6.3% of women and 11.2% of males have some type of cardiovascular disease. A random sample of 200 women and 150 men were assessed for signs of cardiovascular disease. What is the probability that we see a difference smaller than 6%? Q We cannot nd this probability based on the information provided. pnorm(0.06, 0.049, 0.031) = 0.638 O 1- pnorm(0.06, 0.049, 0.029) = 0.352 O 1- pnorm(0.06, 0.049, 0.031) = 0.361 O pnorm(0.06, 0.049, 0.029) = 0.647 True or False: The sampling distribution of a sample proportion and the sampling distribution of the difference between two independent proportions both follow an approximately normal distribution. True O False
