I have some problems in the lesson "The idea of significance test" that I don't know. Please help me, thank you so much.

Question 1:

For the significance test you assume that the null hypothesis is a claimed value. O greater than O less than O not equal to O equal toIn the case that it is right-sided, o is the area in the right tail (right of the critical value). In the case that it is two-sided, o is the area in both tails (with , area in each tail). In this case, there are two critical values. Due to symmetry of the z and t distributions the critical values are always opposites. For significance tests, a is the specified cut-off that the p-value is compared to. It represents the largest probability of making a type I error that the test will allow. A type I error is when the null hypothesis is rejected but the null hypothesis is actually true. If p-value = 0.04 and a = 0.05 then [ Select ] If p-value = 0.23 and a = 0.05 then [ Select ] If p-value = 3.2*10-12 and a = 0.02 then [ Select ] z (or t) scores that are closer to the claimed value of the mean represent z (or t) scores that are likely if the null hypothesis is true. The z (or t) scores in the tails represent z (or t scores) that are unlikely if the null hypothesis is true. The z (or t) score at the cut-off (with a area in the specified tails) are called the critical values. The region in the tail(s) cut-off by the critical value(s) are called the rejection region. Sample Statistic = 2.3, Critical Value = 2.4 then [ Select ] Sample Statistic = 2.3 Critical Value = 2.1 then [ Select ] Sample Statistic = 4.5 Critical Values = -2.1 and 2.1 then [ Select ]Question 14 0.75 pts According to a 2014 research study of national student engagement in the U.S., the average college student spends 17 hours per week studying. A professor believes that students at her college study less than 17 hours per week. The professor distributes a survey to a random sample of 80 students enrolled at the college. Here are the null and alternative hypotheses for her study: H o: u = 17; Ha: u