I have the following question:

Can someone kindly explain to me how we come to (n-1)(n)(2n-1)/6?

Thanks,

Ron

Count the number of times the function f is called range(n) for j in range ): for k in range (j ): En-1 (i - 1)i 2 n-1 2 1 ((n-1)(n)(2n- 1) (n-1)n 2