I have to do the calculations for the blank spaces using the information I obtained from the second picture, but I missed the lecture the day before so I'm having a tough time trying to figure this out myself. If you could show me step by step how you got the answers I would greatly appreciate it.

Key equation: Tf=Kf( solvent )m (solute) freezing temperature depression, Tf Tf=Tf(puresolvent)Tf(solution) molality of solute, m (based on key equation) moles of benzoic acid, nsolute molality = moles solute / mass solvent ( in kg ) Experimental Molecular weight of benzoic acid molecular weight = mass / moles finding this value is the purpose of this lab Theoretical Molecular weight of benzoic acid (what you wrote in the Table of Reagents) Percent error % error = experimental-theoretical )/ theoretical 100% \#Lauric Acid - Solvent - (8.06g)- CH3(CH2)10COOH - white powder flakes, when melted it turned into a clear substance. Initial temp: 71.7C Final temp: 43.0C Mean: 43.0C Benzoic Acid-Solute- (1.01g) - Cults COOH - white shiny/metallic powder flakes Both the Lauric Acid and Benzoic Acid were melted togethe. Initial temp: 74C Final temp: 38.4C Mean: 38.7C