I just can't seem to get the my X = 0.05 when Length = 1. Using step size L of 1.

My k1, k2, k3, k4 are:

k1, k2, k3, k4 = 1*(0.65267*56791.1128*706/2*555.87) = 9.661*10^4

T1 = 0 + 1/6*(9.661*10^4 + 2(9.661*10^4) + 2(9.661*10^4) + (9.661*10^4)) = 9.661*10^4

this clearly isn't 0.05 so pls help. If the differential equation I use to find my k1, k2, k3, k4 is wrong, can show how to derive the correct one and redo everything again.

=0.652670905RNH3=56791.1128kmol/m3.hrA=706m2FN2=135.43kmol/hrX(0)=0L(0)=0 Question: Solve dLdX=2FN2RNH2A using 4th order Runge Kutta method and plot a Conversion (X) vs Length (L) graph using Excel. Please show a detailed working of which values were used how to get the k1, k2 k3 and k4 values using Length =1 as the example Also provide Excel sheet if possible. Note: Please show how to derive the differential equation used for the 4th order Runge Kutta method and what each cell A, B, C, etc. in Excel means too