I just need the answers : for example problem 1 - ans: option ( ), No need to show work

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This print-out should have 19 questions. Determine fry when Multiple-choice questions may continue on the next column or page - find all choices f(x, y) = 2rtan (ry) . before answering 001 10.0 points 1. fry = (1 + x2y2)2 Determine fr when 2ry 2. fry = 1+ x2y2 f(x , y) = (y - 12) (2y2 + I). 2y 3. fry = -7 1+ 2y2 1. fr = y - 4ry - 312 2. fx = Ary- - y - 3x2 Ar 4. fry = 3. fx = 2xy -2y + 312 (1 + 1212)2 4. fx = 2y + 2ry-+ 3x2 2cy 5. fx = 2y - 2xy2 + 3x2 5. fry = 1 6. fx = 4ry- +y -312 4y 002 10.0 points 6. fry = (1 + 12y2)2 Determine fr when 005 10.0 points f(x, y) = xsin(4y - x) + cos(4y - I) . Find fry when f(x, y) = (1 -2y)ery. 1. fx = xcos(4y - r) - sin(Ay - I) 2. fx = -2 sin(4y - I) - I cos(Ay - I) 3. fr = -x cos(4y - I) 1. fry = (2 + ry)(r - 2y)ey 4. fr = -rsin(4y - x) 2. fry = (1+ ry)(x - 2y)ev 5. fr = - cos(4y - r) - r sin(Ay - I) 3. fry = (2+ ry)ery 6. fr = xsin(Ay - I) 4. fry = (1- ry)ery 7. fx = x cos(4y - I) 5. fry = (1 + xy)ery 8. fr = 2sin(4y - r) - r cos(4y - I) 6. fry = (2 - ry)(x - 2y)ely 003 10.0 points 006 10.0 points Find the slope in the r-direction at the Evaluate the double integral point P(0, 2, f (0, 2) ) on the graph of f when f (I, y) = 2(2x + y)e zy . 1 = 2dady with 1. slope = -6 2. slope = 0 A = (1, y) : 45156, 35456) 3. slope = -4 4. slope = by first identifying it as the volume of a solid. 5. slope = 1. I = 10 004 10.0 points 2. I = 143. I = 16 TZ 4. I = 12 5. 1 = 18 007 10.0 points The graph of the function z = f (x, y) = 8-x is the plane shown in Determine the value of the double integral 1 = [ f(z, y) dady over the region A = (1,y) : 0SIS3, 05456) in the ry-plane by first identifying it as the volume of a solid below the graph of f. 1. I = 115 cu. units 2. I = 117 cu. units Determine the value of the double integral 3. I = 113 cu. units 4. I = 114 cu. units 1 = [ f(z, y) didy 5. I = 116 cu. units over the region 009 10.0 points A = (x,y) : 0SIS8, 0Sys6) Find the value of the integral in the ry-plane by first identifying it as the volume of a solid below the graph of f. 1. I = 194 cu. units when 2. I = 192 cu. units f(x, y) = 5r + Ary. 3. I = 195 cu. units 4. I = 196 cu. units 1. 1 = 5 5. I = 193 cu. units -y 2 008 10.0 points 5 4 2. 1 = The graph of the function 3. I = 5y + 2y2 z = f(x, y) = 8-x is the plane shown in 4. I = 5y + 4y2Evaluate the iterated integral 5. 1= 5 + 41 I = holetype dady. 6. I + 010 10.0 points 1. I = In (2) Determine the value of the double integral 2. I = 21n (2) 1 = [ f(z, y) dady 3. I = = In (2) when f(r, y) = 3 and A = (1, y) : 15x53, 4 54 56) 4. I = - In 1. I = 10 5. 1 = 21n 2. I = 9 6. 1 = In 3. I = 11 013 10.0 points 4. I = 13 Evaluate the iterated integral 5. 1 = 12 011 10.0 points Evaluate the integral 1. I = 41n 1 = J. / (42 + 327y ) dydiz. 2. 1 = 15 In (4) 2 1. I = 4 15 3. 1 = - In (15) 2. I = 5 4. I = 15 In (4) 3. 1 = 5 5. I = 41n (15) 4. I = 3 6. I = 15 In 5. 1 = 014 10.0 points 012 10.0 points The solid shown inN lies below the graph of lies below the graph of z = f(x, y) = 1+x-y- z = f(x, y) = 4+x2 -y2 above the rectangle -1