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I know when I find T n (x) of f(x)= x cos(4x) , where a=0, n=5, and -0.3
I know when I find Tn(x) of f(x)= x cos(4x) , where a=0, n=5, and -0.3 <= x <= 0.3 the taylor series expansion is
T5(x) = x - 8x3 + (32/3)x5
But how do I investigate the accuracy of my approximation by finding an upper bound for abs[Rn(x)] when x lies in the given interval? to 6 decimal places.....
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