I need a professional explanation for Hexconvertor emu8086 code, in 3 pages as a word text

; hex convertor. ; this example converts a 2 digit hexadecimal number ; into a numeric value and then into decimal/ascii string representation, ; and finally it prints out the result in binary code.

; to see decimal string: ; 1. click "vars" ; 2. click "result" variable ; 3. enter "3" for the elements and "ascii" for show as.

name "hex"

org 100h

jmp start

; source hex value is 2 char string. ; numeric value is stored into temp, ; and string decimal value is stored into result.

source db '1b', 0 ; 1bh is converted to 27 (decimal) 00011011b (binary) result db '000', 0 temp dw ?

start: ; convert first digit to value 0..15 from ascii: mov al, source[0] cmp al, '0' jae f1

f1: cmp al, '9' ja f2 ; jumps only if not '0' to '9'.

sub al, 30h ; convert char '0' to '9' to numeric value. jmp num1_ready

f2: ; gets here if it's 'a' to 'f' case: or al, 00100000b ; remove upper case (if any). sub al, 57h ; convert char 'a' to 'f' to numeric value.

num1_ready: mov bl, 16 mul bl ; ax = al * bl

mov temp, ax

; convert second digit to value 0..15 from ascii: mov al, source[1] cmp al, '0' jae g1

g1: cmp al, '9' ja g2 ; jumps only if not '0' to '9'.

sub al, 30h ; convert char '0' to '9' to numeric value. jmp num2_ready

g2: ; gets here if it's 'a' to 'f' case: or al, 00100000b ; remove upper case (if any). sub al, 57h ; convert char 'a' to 'f' to numeric value.

num2_ready: xor ah, ah add temp, ax ; convertion from hex string complete! push temp ; store original temp value.

; convert to decimal string, ; it has to be 3 decimal digits or less:

mov di, 2 ; point to top of the string.

next_digit:

cmp temp, 0 je stop

mov ax, temp mov bl, 10 div bl ; al = ax / operand, ah = remainder. mov result[di], ah add result[di], 30h ; convert to ascii.

xor ah, ah mov temp, ax

dec di ; next digit in string. jmp next_digit

stop: pop temp ; re-store original temp value.

; print result in binary: mov bl, b.temp mov cx, 8 print: mov ah, 2 ; print function. mov dl, '0' test bl, 10000000b ; test first bit. jz zero mov dl, '1' zero: int 21h shl bl, 1 loop print

; print binary suffix: mov dl, 'b' int 21h

; wait for any key press: mov ah, 0 int 16h

ret ; return to operating system.