I need answers to question 2, 3 and 4. May you please provide the calculations to the equations for answers. I provide the prompt, the graph, and excel data.

Vertical 1400 1200 1060 400 200 D SO 150 200 250 3:00KIN 300 - Biomechanics of Human Movement Lab 5: Linear Kinetics Name Date Orientation: Most of our movements ultimately rely upon our interaction with the ground. We are constantly pushing against the ground both vertically and horizontally as we initiate and modify movements of the total body and body segments (i.e., performing a push up, or vertical jumping). Because of the importance of our interactions with the ground in the generation and modulation of our movements, the ground reaction force (GRF) could arguably be considered the most important external force acting on the body. What is important to keep in mind is that the GRF is largely under our control via coordinated muscle actions. By producing a certain combination of muscle actions, we ultimately push against the ground which pushes back against the body with an equal and opposite force. This is explained by Newton's 3rd law of motion which states that for every action there is an equal and opposite reaction. This experiment examines the difference in maximal countermovement jump height between using the force plate and using flight time. When using the Force Plate: According the impulse-momentum relationship, if the jumper initiates the upward phase of the jump from a resting state (v; = 0; either from a squat or bottom of a countermovement), the impulse generated by the athlete can be used to calculate the velocity of the center of mass (CM) at the instant of takeoff: Impulse = Momentumfinal - Momentum Initial ImpulseTotal - ImpulseBW = Impulse jump ImpulseTotal - ImpulseBw = m(vf - vi) (Average GRF * t) - (Bodyweight * t) = m(vf - vi) (Average GRF * t) - (Bodyweight * t) of = m where m is the body mass, v; is the vertical velocity at the beginning of the upward movement, and vy is the vertical velocity at the instant of takeoff.This vertical takeoff velocity can then be used with the equations of uniformly accelerated motion (projectile motion) to calculate the height to which the COM was elevated during the jump. Height = 2g where g is the acceleration due to gravity, v; is the vertical velocity vertical velocity at the instant of takeoff, vy is the vertical velocity at the apex of the flight, and Ay is the vertical displacement. When using Flight Time: The time at which a person is in the air (when ground reaction force is zero) can be used to determine jump height. Note that flight time consists of two halves: rising and falling. Therefore, your calculation must reflect 1/2 of the full time in the air: Height = vit + 29tz Assignment #1 (5 points): Complete the following questions. The answers to questions need to be written in complete sentences. Copy and paste figures and math responses into the same word document as your written responses. Upload your lab document onto the Canvas site. All data needed for this assignment are provided on Canvas in excel format. 1. Create a figure of the vertical GRF versus time of the countermovement jump. Create a dotted horizontal line for bodyweight. Using a software such as Paint, label with the following: a line where body weight is, bottom of squat, and toe off. 2. On your word document, solve for jump height using the impulse-momentum relationship. Write out your calculations step by step. 3. On your word document, solve for jump height using flight time. Write out your calculations step by step. Flight time can be obtained from the excel spreadsheet. 4. Using the two heights you calculated in Questions 2 & 3 answer the following questions: a. Which method produced the largest jump height and how significant is the difference? b . What are some limitations for each method