I need help in this question. Please I also posted the solution to same question with different values. Please use same method and solve both so i can get correct answers

Benefit-Cost Ratio 2: Consider three alternatives, each with a 6-year useful life (note: there is no Moe). If the MARR is 5.3%, which alternative should be selected? Solve this problem using incremental benefit-cost ratio analysis. You will need to do two incremental B/C ratios. You must give the ratios of each to within one hundredth (like 1.24) and identify which alternatives are being increment against each other. Eeny Meeny Miny Cost $5500 $2034 $1010 UAB $1148 $469 $264 First Ratio: Answers: Select? Reasoning/Work: Second Ratio: 9-30: Consider three alternatives, each with an 8-year useful life (note: there is no Moe). If the MARR is 9%, which alternative should be selected? Solve this problem benefit-cost ratio analysis. Eeny Meeny Miny Cost $6875 $2543 $1262 UAB $1275 $521 $293 Answer: Miny pts> Reasoning/Work: First make sure each project individually make or exceeds the MARR: (B/C) eeny = 1275(P/A,9%,8)/6875 = 7056.89/6875 = 1.03 B/C 21.00 means that it meets or exceeds MARR. (B/C)Meeny = 521(P/A,9%,8)/2543 = 2883.64/2543 = 1.13 B/C 2 1.00 means that it meets or exceeds MARR. (B/C)miny = 293(P/A,9%,8)/1262 = 1621.70/1262 = 1.29 B/C > 1.00 means that it meets or exceeds MARR. So they each meet the MARR and next we increment the B/C's (note the "Do Nothing" is essentially eliminated since the lowest cost meets the MARR via B/C > 1.00. So, in order of cost ... Meeny-Miny incrementAB/AC = (521-293)(P/A,9%,8)/(2543-1262)=228(P/A,9%,8)/1281=1261.94/1281=0.99 This means that the higher cost Meeny loses and the lower cost Miny becomes the defender against Eeny, so Eeny - Miny incrementAB/AC = (1275-293)(P/A,9%,8)/(6875-1262)=982(P/A,9%,8)/5613=5435.19/5613=0.97 This means that the higher cost Eeny loses and the lower cost Miny so select Miny