I need help on these questions

Differential Equations Fish Population Example de = 0.20P - 10 Given the example, finish filling out the table using the differential equations at 6 7 8 t (years) 0 1 5 P(millions) 60 2 62 64.4 3 4 74.89 67.28 70.74 Fish Population Example Using the solution P = 50 + 10ed.20t (more exact) to the differential equation at = 0.20P - 10 (estimated without the decimals from the value of e), create a new table with values t (years) 0 7 1 2 5 6 8 4 P(millions) 3 Example "ONLY RATE OUT" Differential Equation: de = kQ (where if k is positive "growth" and if k is negative "decay") Solution: Q = Cekt (again sign of k depends on if exponential growth or decay) Application Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 1.1 million barrels of oil in the well; six years later 500,000 barrels remain. At what rate was the amount of oil in the well decreasing when there were 600,000 barrels remaining? NOTE: For full credit do not just copy my k value, show the STEPS on how to solve