I need help perform the chi-square test. Round your x2 to three decimal places and round your p-value to four decimal places. behaviors of 65 students were compared to behaviors of 57 non students. One of the questions was "when asked to decide on a password I used my mother's maiden name." 24 of the students agreed with this statement and 27 of the nonstudents agreed also.

I have figured the data in a two-way table: Students Nonstudents Total

Agreed: 24 27 51

Disagreed: 41 30 71

Total 65 57 122

x2=__________

df_=_____________

P-value=__________________

Summarize the results; We can or cannot conclude at the 5% level that students and nonstudents differ?

If we reanalyze the data using the methods for comparing two proportions . Compare the result and verify that the Chi-Square statistic is the square of z statistic.( Test students who agreed minus nonstudents who agreed and round your z to two decimal places and round your P-value to four decimal places.

z=_________________

P-Value=_____________________

Thank you