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I need help to solve this exercise Show that a solution of the differential equation subject to the boundary conditions (a) = k0 and(b) =

I need help to solve this exercise

Show that a solution of the differential equation subject to the boundary conditions (a) = k0 and(b) = k1, where k0 and k1 are constant potentials, is given by (r) = A loge r + B, where

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ko - K1 ko loge b + K1 log, a A= log (a/b) y B log (a/b)

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