i need help with my code so it looks like the example

Write a C++ program which prompts the user for the following:

The loan amount (220,000); the interest rate (5.4); and the length of the loan in years (30). Print out the payment period; Interest; Principle; and Balance for each month. Print the total Interest at the end. (if for some reason your program does not print all 360 payments you can add a cin.get() at the end of your code and that should take care of the issue)

Please enter your beginning balance in dollars.

220000

Please enter your annual interest rate in percent.

5.4

Please enter your payment terms in years.

30

Your Monthly Payment is: $1235.37

Period Interest Principal Balance

1 $990.00 $245.37 $219754.63

2 $988.90 $246.47 $219508.16

3 $987.79 $247.58 $219260.58

4 $986.67 $248.70 $219011.88

5 $985.55 $249.81 $218762.07

6 $984.43 $250.94 $218511.13

7 $983.30 $252.07 $218259.06

8 $982.17 $253.20 $218005.86

9 $981.03 $254.34 $217751.52

10 $979.88 $255.49 $217496.03

11 $978.73 $256.64 $217239.40

12 $977.58 $257.79 $216981.61

.......

358 $16.53 $1218.84 $2454.16

359 $11.04 $1224.32 $1229.83

360 $5.53 $1229.83 $-0

code:

#include #include #include #include #include #include #include

using namespace std;

int main() { double M = 0.0; double pay = 0.0; double ment = 0.0; double payment = 0.0; double P = 0.0; double i = 0.0; double N = 0.0; cout << setprecision(2) << fixed; cout << "Please enter your beginning balance in dollars. " << endl; cin >> P; cout << "Please enter your annual interest rate in percent. " << endl; cin >> i; cout << "Please enter your payment terms in years. " << endl; cin >> M; i = (i / 100.0) / 12.0; N = M * 12.0; pay = ((pow((1.0 + i), N)) * i); ment = ((pow((1.0 + i), N)) - 1.0); payment = P * ((pay) / (ment)); cout << "Your Monthly Payment is: $" << payment << endl; double balance = P; for (double e = 0.0; i <= N; e++){ double interest = P * i; double principal = payment - interest; balance = P - principal; cout << "Period Interest Principal Balance" << endl; cout << e << "\t" << interest << "\t" << principal << "\t" << balance << endl; } return 0; }