I need help with the following Lisp problem if you could include comments explaining your work so I can learn and better understand how you solved it that would be deeply appreciated!
a sublist consisting of the count and the item which repeats. If the list has sublists, treat them as single items; don't change them or try to compress the sublists. If an item is not repeated, leave it unchanged, with one exception: an existing item is a sublist beginning with a positive number, and does not repeat, it should be changed to a pair with a repeate count of 1. For instance, a sublist (3 spoons) which does not repeat should be converted to (1 (3 spoons)). The purpose of this rule is to avoid confusion so it is possible to create a reliable decompress function which will always recreate the original list. Here are some examples: 1sp (load "compr. lsp) compr 15p> (compr '(a bw goober goober ccc tom fred fred)) (a bw (2 goober) (3 c) tom (2 fred)) lsp> (compr '(nothing here to change)) (nothing here to change) 1sp (compr '((a bc) (a bc) (a bc) (def) (4 5 6) (-3 -5 -7) 10 12 ) ) ) (13 (a b c)) (def) (1 (4 5 6)) (-3 -5 -7) 10 12) 1sp> (compr '(thing thing (a b) (a b) (a b)(b a) thud wumpus)) ((2 thing) (3 (a b)) (ba) thud wumpus) 1sp (compr '(oooh oooh oooh oooh oooh)) ((5 oooh)) Use the equal? function to decide if adjacent items are the same. (Don't use -, since is only for comparing numbers.) Hints You are free to define any number helper functions in addition to compr, and you will probably need to. I defined a function pref which tells the number of times the first item in a list repeats, like this: 1sp(pref '(a a a bbccccc)) 1sp(pref '(a b c d)) 1sp (pref '( Another useful utility is the badly named built-in first-but function, which strips the first n items in a list, as: 1sp>(first-but 4 (a b c d e f g h i j)) (e f ghi il 1sp> (first-but 5 (a bc) nil 1sp> (first-but I '(hi there ) ) (there) At cach step, if pref shows a number greater than one (or if the item is a sublist starting with a positive number) you can use first-but to remove that number of items and replace it with the correct sublist. a sublist consisting of the count and the item which repeats. If the list has sublists, treat them as single items; don't change them or try to compress the sublists. If an item is not repeated, leave it unchanged, with one exception: an existing item is a sublist beginning with a positive number, and does not repeat, it should be changed to a pair with a repeate count of 1. For instance, a sublist (3 spoons) which does not repeat should be converted to (1 (3 spoons)). The purpose of this rule is to avoid confusion so it is possible to create a reliable decompress function which will always recreate the original list. Here are some examples: 1sp (load "compr. lsp) compr 15p> (compr '(a bw goober goober ccc tom fred fred)) (a bw (2 goober) (3 c) tom (2 fred)) lsp> (compr '(nothing here to change)) (nothing here to change) 1sp (compr '((a bc) (a bc) (a bc) (def) (4 5 6) (-3 -5 -7) 10 12 ) ) ) (13 (a b c)) (def) (1 (4 5 6)) (-3 -5 -7) 10 12) 1sp> (compr '(thing thing (a b) (a b) (a b)(b a) thud wumpus)) ((2 thing) (3 (a b)) (ba) thud wumpus) 1sp (compr '(oooh oooh oooh oooh oooh)) ((5 oooh)) Use the equal? function to decide if adjacent items are the same. (Don't use -, since is only for comparing numbers.) Hints You are free to define any number helper functions in addition to compr, and you will probably need to. I defined a function pref which tells the number of times the first item in a list repeats, like this: 1sp(pref '(a a a bbccccc)) 1sp(pref '(a b c d)) 1sp (pref '( Another useful utility is the badly named built-in first-but function, which strips the first n items in a list, as: 1sp>(first-but 4 (a b c d e f g h i j)) (e f ghi il 1sp> (first-but 5 (a bc) nil 1sp> (first-but I '(hi there ) ) (there) At cach step, if pref shows a number greater than one (or if the item is a sublist starting with a positive number) you can use first-but to remove that number of items and replace it with the correct sublist
