I need help with the following:

Problem 13-4

On average, 4 customers per hour use the public telephone in the sheriff's detention area, and this use has a Poisson distribution. The length of a phone call varies according to a negative exponential distribution, with a mean of 5 minutes. The sheriff will install a second telephone booth when an arrival can expect to wait 3 minutes or longer for the phone.

Formula: Wq = ^ (u(u-^) solve for lamda,

a)By how much must the arrival rate per hour increase to justify a second s telephone booth?

b)Suppose the criterion for justifying a second booth is changed to the following: Install a second booth when the probability of having to wait at all exceeds 0.6. Under this criterion, by how much must the arrival rate per hour increase to justify a second booth?