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Question 6 A film of liquid of thickness d = 6.00 um lies on the surface of a piece of glass. Monochromatic light is incident on the film from air. answered The wavelength of the light in air is > = 0.504 um. The index of refraction of air can be approximated as 1.00, the index of refraction of the liquid is my = 1.26, and the index of refraction of glass is n, = 1.50. Marked out of There are two interfering rays, as shown in the figure below (Figure 1). P Flag question 1 2 air liquid glass Figure 1. A ray in air interacts with liquid on glass. The angle of incidence is 0. Ray 1 reflects off the air-liquid surface, and ray 2 reflects off the liquid-glass surface and makes an angle 01 with the normal. Part 1) What is the phase of the reflected ray, ray 1, off the air-liquid boundary? Pray 1 = radians What is the phase of the reflected ray, ray 2, off the liquid-glass boundary? Pray 2 = radians Part 2) How is the angle 01 of the refracted ray related to the incident angle 0? Give an algebraic expression that includes 0 (type "theta") and ni (type "n_!"). sin 01 = Part 3 Consider light that is normally incident on the liquid, that is, 0 = 0. Calculate the phase difference between rays 1 and 2. $ = radians Do the rays interfere constructively or destructively? (No answer given) *