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I need help writing a conclusion for my lab . Conclusions: This is a summary of the findings of the work. It may have redundancy

I need help writing a conclusion for my lab .

Conclusions: This is a summary of the findings of the work. It may have redundancy in part to what is mentioned in the abstract and in the results sections.

The Abstract:In other words, that it is not weighted or in any other way designed to favor falling with heads up or to favor falling with tails up. If this is true of my coin, then my prediction is that the probability of flipping heads is 0.5, and the probability of flipping tails is also 0.5. This means that I am predicting that of the time the coin will come up heads, and of the time it will come up tails. So the first lab we test the effect of adhesive tape placed on one side of the coin ips by simultaneously flipping a regular coin and a coin with twenty squares of adhesive tape placed on one side. For the second lab we did the same steps but we tested the chi-square of independence using a 2 x 2 contingency table used to test the difference in outcomes at the five percent level of probability. For the first lab I got.72 foer coins without tape and I got 8 for the coin with tape .Now that we have the chi-square number, you must determine how significant that value is. Remember that the chi-square value tells you the difference between the results that you got and the results that you expected to get.

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Results: Lab 1 Coins with tape Coins with tape Coins without tape Coins without tape Heads 22 Tails Heads Tails 28 35 15 25 25 25 25 Number of coin flips observed Number of coin flips expected (observed expected)2/ expected (observed - expected)2 expected (x2) .36 .36 4 .72 .72 8 8 expected (x2) Tails Total 14 50 Lab 2: Variable Heads Coin with Ten pieces 36 of tape Coin with 20 pieces 41 of tape Total 77 9 50 23 100 This chi-square can be calculated by the following formula where the values are taken from the 2 x 2 contingency table (Table 1): X2=1.41 Results: Lab 1 Coins with tape Coins with tape Coins without tape Coins without tape Heads 22 Tails Heads Tails 28 35 15 25 25 25 25 Number of coin flips observed Number of coin flips expected (observed expected)2/ expected (observed - expected)2 expected (x2) .36 .36 4 .72 .72 8 8 expected (x2) Tails Total 14 50 Lab 2: Variable Heads Coin with Ten pieces 36 of tape Coin with 20 pieces 41 of tape Total 77 9 50 23 100 This chi-square can be calculated by the following formula where the values are taken from the 2 x 2 contingency table (Table 1): X2=1.41

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