I need my homework checked, but Chegg won't let me upload more than one image. Please check my answers and correct any that are wrong. Here's the answers that I have:

Part A

$-$ total time $($convert hrs to sec$)$: $8*60*60=28,800$ seconds

$-$cycle time $($available time during day $/$ unites require per day$)=120$

$-$therefore, the max time for each work station is $120$ seconds

Work Station $($WS$)1$: Task A $(60$ sec$)+$ Task C $(20$ sec$)=80$ seconds $($idle: $40)$

WS$2$: Task B $(80)=80$ sec $($idle: $40)$

WS$3$: Task D $(50)+$ Task F $(30)=80$ sec $($idle $40)$

WS$4$: Task E $(90)=90$ sec $($idle $30)$

WS$5$: Task G $(30)+$ Task H $(60)=90$ sec $($idle $30)$

Part B $[$Answers$]$

$-$work station w the highest total task time dictates the output rate, $[$so Work Station $4]$

$-$ cycle time $=[120$ seconds$]$

$-$capacity utilization ratios CUR: task time$/$cycle time multiplied by $100$

WS$1[66\mathrm{.}67\%]$

WS$2[66\mathrm{.}67\%]$

WS$3[66\mathrm{.}67\%]$

WS$4[75\%]$

WS$5[75\%]$

$-$Efficiency: sum of task times $/$ # of WS$*$cycle time $*100$

Efficiency: $230/600*100=[70\%]$

$5.[$Yes$]$

$6.[$Work Station $4]$ is the bottle neck bc it has the longest processing time

$7.$ Inventory will accumulate before WS$4$ because it has the longest processing time and will slow down the system's flow.