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STAT 202 Q1. A survey of 345 men showed that the mean time spent on daily grocery shopping is 15 mins. From previous record we knew that or = 3 mins. Find the 98% condence interval for population mean. Q2. A poll of 140 students shows that the mean time spent weekly on cloths laundry is 150 mins. We don't have previous record on population standard deviation, and so from the sample we computed sample standard deviation and found that 3 = 10 mins. Find the 95% condence interval for the population mean. Q3. A business man want to decide about the hair-cut prices and so he decided to know the mean time spent on hair-cuts. He has no record of time needed for hair-cut. He wanted a max error of :|:0.2. He took a sample of size 30 and found that s = 1.5 min. Find the sample size needed to achieve the 95% condence level. Q4. Formulate the null and the alternative hypothesis and show which one of those statement is the claim. (a) It's claimed that the time needed to prepare German chocolate cake of diameter 25 cm is 110 mins. (b) Survey showed that more than 69% of oil companies employees are concern about their health. (c) A poll showed that less than 65% of college students are satised with their learning process. Q5. The director of factory believes that the average of labour spent on daily break is more than 100 mins. A sample of size 40 is tested and found that the average of labour Spending as a break is 101.5 mins. From previous records it's known that the standard deviation of time spent as a daily break is 4 mins. With a signicance of 0.05 test the claim on the time Spent as a break. Q6. A new hair-styler wants to decide about the hair-colouring pricing and she believes that standard hair colouring should be charged no less than 330. She has no record on hair-colouring prices. She took a sample of size 20 and asked about money they are charged for and she found that s = $4.5 and sample means is $28. Decide about the claim that she believes in using a signicance level of 0.025