I need to see the calculations for how the answer for the standard normal value arrived and the margin of error. I think the z score was used ( I'm still having trouble understanding z score.

Questions Count Count Poor Total Good (G) (P) Surveys Good (G) % Room Quality 153 47 200 76.5% Food Quality 148 52 200 74.0% Service Quality 143 57 200 71.5% Total No. of (G) & (P) 444 156 600 74.0% Quality of Service Count % Satisfied 110 55.0% Dissatified 90 45.0% Tota 200 100% 92% confidence interval for the proportion of all 92% confidence inter recent clients that were " dissatisfied." recent clients who answ # of Respondents n 200 # of Respondents # of Events 90 # of Events Proportion of Events 0.45 Proportion of Events Proportion of Non-Events 0.55 Proportion of Non-Events Standard Error (SE) sqrt(p*q) 0.0351781182 Standard Error (SE) Confidence 0.92 Confidence Level of Significance 0.08 Level of Significance Two Sides a/2 0.04 Two Sides Standard Normal Value Z -1.7506860713 Standard Normal Value Margin of Error -0.1232 Margin of Error Formula = 2 x z V(p-(1-p)) Formula = 2 x z V(P-(1-F Lower Limit p+Z*SE 0.3884141585 Lower Limit Upper Limit P-Z*SE 0.5115858415 Upper Limit