Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

I need to use the Adapter Design pattern in Java for the two incompatible interface Card and Ka (Card in Chinese language). Here is the

I need to use the Adapter Design pattern in Java for the two incompatible interface Card and Ka (Card in Chinese language). Here is the code for both the interfaces and the classes implementing these interfaces:

Card interface:

public interface Card { /**  * Gets rank.  *  * @return the rank  */  Rank getRank(); /**  * Gets suit.  *  * @return the suit  */  Suit getSuit(); }

CardImpl class:

public class CardImpl implements Card{ private RankEnum rank; private SuitEnum suit; /**  * Instantiates a new Card.  *  * @param rank the rank  * @param suit the suit  */  public CardImpl(RankEnum rank, SuitEnum suit){ this.rank = rank; this.suit = suit; } /**  * Its a getter method for the Rank.  */  @Override public RankEnum getRank() { return rank; } /**  * Its a setter method for the Rank.  */  @Override public SuitEnum getSuit() { return suit; } } 

Ka interface:

public interface Ka { int getRank(); int getSuit(); }

kaShiXia class:
public class kaShiXia implements Ka { public kaShiXia(KaDengJEnum kaHao, int suit) { if (kaHao == null) { throw new IllegalArgumentException("ill-formed ka"); } validateSuit(suit); this.kaHao = kaHao.value; this.suit = suit; } /**  * private method to determine if a suit is within range  *  * @param suit  */  private void validateSuit(int suit) { if ((suit < 0) || (suit > 4)) { throw new IllegalArgumentException("ill-formed ka"); } } /**  * Instantiates a new ka shi xia.  *  * @param kaHao the ka hao  * @param suit the suit  */  public kaShiXia(int kaHao, int suit) { validateSuit(suit); if ((kaHao < 0) || (kaHao > 12)) { throw new IllegalArgumentException("ill-formed card"); } this.kaHao = kaHao; this.suit = suit; } /*  * @see diErBao.Ka#getRank()  */  public int getRank() { return kaHao; } /*  * @see diErBao.Ka#getSuit()  */  public int getSuit() { return suit; } @Override public String toString() { return kaHao + " of " + KaPianTaoZhuangEnum.getKaPianTaoZhuang(getSuit()); } public boolean equals(Object object) { if (object instanceof Ka) { kaShiXia ka = (kaShiXia) object; return (ka.kaHao == this.kaHao && ka.suit == this.suit); } else  return super.equals(object); } @Override public int hashCode() { return Objects.hash(kaHao, suit); } /**  * Enum of card suits  */  public enum KaPianTaoZhuangEnum { xin, tieQiao, zuanShi, juLeBu; // hearts, spades, diamonds, clubs   private static KaPianTaoZhuangEnum[] list = KaPianTaoZhuangEnum.values(); public static KaPianTaoZhuangEnum getKaPianTaoZhuang(int i) { return list[i]; } } /**  * Enum of card ranks  */  public enum KaDengJEnum { TWO(0b0101), THREE(0b1001), FOUR(0b1101), FIVE(0b0100), SIX(0b1000), SEVEN(0b1100), EIGHT(0b0011), NINE(0b0111), TEN(0b1011), JACK(0b0010), QUEEN(0b0110), KING(0b1010), ACE(0b0001); private int value; private KaDengJEnum(int value) { this.value = value; } public static KaDengJEnum lookupEnumName(int correspondingValue) { for (KaDengJEnum kaRank : KaDengJEnum.values()) { if (correspondingValue == kaRank.value) return kaRank; } return null; } } private final int kaHao; // card number  private final int suit; }

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Building Database Driven Catalogs

Authors: Sherif Danish

1st Edition

0070153078, 978-0070153073

More Books

Students also viewed these Databases questions

Question

=+ Are they breakable for any reason?

Answered: 1 week ago

Question

=+When and under what circumstances are contracts renegotiated?

Answered: 1 week ago