Answered step by step
Verified Expert Solution
Link Copied!

Question

00
1 Approved Answer

I need you to modify this code using java: Please add comments to the code as explain what is done in the method. List of

I need you to modify this code using java: Please add comments to the code as explain what is done in the method.

List of methods you have to implement

In the MyLinkedList class

private MyLinkedList reverse(ListNode node)

private ListNode reverse(ListNode prev, ListNode subHead)

In the Tester Class

public int countSpace(String str)

public boolean myContains(String s1, String s2)

public int div(int m, int n) throws IllegalArgumentException

private boolean isSum24(int arr[], int targetSum)

private void reverseArray(int a[], int low, int high)

private void recursiveSelectionSort(int a[], int low, int high)

Here is the code:

public class MyLinkedList { private ListNode head; private int size; /** * inner class for ListNode */ private class ListNode { private Object data; private ListNode next; private ListNode(Object d) { this.data = d; this.next = null; } private ListNode() { } } /** * Constructor of linked list, creating an empty linked list * with a dummy head node. */ public MyLinkedList() { this.head = new ListNode(null); //an empty list with a dummy head node this.size = 0; } /** * This method reverses the order of data items in this list. Particularly, * the first data item (stored in the node succeeding the dummy node) in the original list * becomes the last item in the resultant reversed list, * the second data item in the original list (the one succeeding the first data item) * becomes the second last item in the reversed list, and so on. * This method invokes a recursive helper method, which * you have to write right below this method. * Note: when you reverse the data items, please do NOT reverse the dummy * head node. Instead, keep a dummy head node in the reversed list. * * You are allowed to create *new* list node when building the returned LinkedList object. * You are NOT allowed to change method signatures that have been provided. * You are NOT allowed to change the provided implementation in the *public* method reverse(). * * @return A new linked list object that contains the original data set, * but in a reversed order. The returned linked list object has a * dummy head node at the beginning of the list. */ public MyLinkedList reverse() { // Please implement this recursive helper method below. // You have to use recursion. return reverse(this.head.next); } /** * * Implement the private reverse(ListNode node) method using recursion. * You are allowed to add helper method into this class if needed. * @param node -- the reference of the first data node(successor of the dummy) in the original list. * @return A new MyLinkedList object contains the same set of data items, but in a reversed order. */ private MyLinkedList reverse(ListNode node) { return null; // change this line of code as needed } /** * This method reverse2() will reverse all data nodes in this list, WITHOUT * creating(introducing) new list nodes, by simply re-wiring the next reference in * the existing list node. For example, list1 = []>[A]>[B], * the reversed list1 will be []-->[B]-->[A], * after assigning node A to B's next reference and setting A's next to null. * */ public void reverse2() { if(this.size <= 1) return; // The following method call works on a *sublist* without a Dummy Node. // Namely, we preserved the OLD dummy head node in the reversed list. this.head.next = reverse(this.head.next, this.head.next.next); } /** * Please implement the helper method below for reverse2(). * @param first, the first node of the list to be reversed. * @param second, the second node of the list to be reversed. * @return the new head node of the reversed list. * Note: you are NOT allowed to create new list node, but have to * re-wiring the existing nodes by changing their next references. * Write this method using recursion. */ private ListNode reverse(ListNode first, ListNode second) {

return null; //change this line of code as needed. } /** * Please do NOT change this method. Instead, you have to include it * into you source code. * @param elem */ public void addFirst(Object elem) { ListNode nn = new ListNode(elem); nn.next = this.head.next; this.head.next = nn; this.size ++; } /** * Please do NOT change this method. Instead, you have to include it * into you source code. * Dump this list into a single string. * @return A string */ public String toString() { String result = "{"; for (ListNode node = this.head.next; node != null; node = node.next) { result += node.data; if(node.next != null) result += "->"; } return result + "}"; }

}

_______________

/** * Please change this file in the places only when it is directed * by the comments. * */ import java.util.Arrays;

public class Tester { public static MyLinkedList list1 = new MyLinkedList(); public static MyLinkedList list2 = new MyLinkedList(); public static MyLinkedList list3 = new MyLinkedList(); //init() method is NOT allowed to change public void init(){ list2.addFirst("C"); list2.addFirst("B"); list2.addFirst("A"); list2.addFirst("D"); list3.addFirst("A"); list3.addFirst("B"); } // Implement the following method using recursion // The method returns the number of white spaces in the input string str. // Write this method below. public int countSpace(String str) { return -1; //change this line of code as needed.}

//Check whether s1 is a substring in s2. //For example, if s1="an", and s2="banana", it returns true. //For another example, if s1="bb" and s2="good", it returns false. //If either s1 or s2 is null, return false. //If either s1 or s2 is empty, return false. //You are NOT allowed to use the contains() method in Java String class. //Write the method below using recursion. public boolean myContains(String s1, String s2){ return false; //change this line of code as needed.} // Compute the quotient of the integer division of (m / n) using recursion, // you are NOT allowed to use mathematics operation '/'. // Look the problem from another perspective. What does the division mean? // Division (m/n) also means how many n (s) is contained in the number m. // If n == 0, throw an IllegalArgumentException object. // Write this method below using recursion. public int div(int m, int n) throws IllegalArgumentException {return -1; //change this line of code as needed.} //Check whether the sum of array arr is 24 or not.//You are required to implement the *private* helper method in the space below this method. //You are NOT allowed to change the provided code in the *public* //method isSum24(int arr[]). public boolean isSum24(int arr[]){return isSum24(arr, 24);} // Implement the private helper method below using recursion. // The method checks whether the sum of all elements in arr // equals to the targetSum or not.// Hint:the subproblem is about a subarray. private boolean isSum24(int arr[], int targetSum) {return false; //change this line of code as needed.} //You are NOT allowed to change the provided code in the *public* public void reverseArray(int a[]) {reverseArray(a, 0, a.length - 1);} //Please write the private reverseArray() using recursion. //The method will reverse the array elements // that are located at indices ranging from low to high. //E.g. if int a[] ={3, 1, 5, 4}, after reverseArray(a, 0, 3) is called,// array a becomes {4, 5, 1, 3}. private void reverseArray(int a[], int low, int high) { } //You are NOT allowed to change the provided code in the *public* public void recursiveSelectionSort(int a[]) {recursiveSelectionSort(a, 0, a.length - 1); //} //Please write the private helper method recursiveSelectionSort() using recursion. //The method will sort in an ascending order the array elements // that are located at indices ranging from low to high.//This is a version of recursive selection sort. private void recursiveSelectionSort(int a[], int low, int high) { }//end of method

//Please do NOT change the main() method below. //If you do change, you get a zero for this project.

public static void main(String[] args) {Tester test = new Tester();test.init();System.out.println("---------Test Reverse()-------"); System.out.println(list1.reverse()); System.out.println(list2.reverse());System.out.println(list3.reverse());System.out.println("-------Test Reverse2()---------"); list1.reverse2(); list2.reverse2(); list3.reverse2(); System.out.println(list1);System.out.println(list2); System.out.println(list3); System.out.println("-------Test countSpace()----------"); System.out.println(test.countSpace("g d "));System.out.println(test.countSpace("good "));System.out.println(test.countSpace(" good")); System.out.println(test.countSpace("good mornin g ")); System.out.println("-----Test myContains()------------");System.out.println( test.myContains("an", "banana"));System.out.println( test.myContains("bn", "banana")); System.out.println( test.myContains("er", "richer"));System.out.println( test.myContains("a", "a"));System.out.println("-----Test div()------------"); System.out.println( test.div(11, 3) );System.out.println( test.div(12, 5) ); System.out.println( test.div(4, 4) ); System.out.println( test.div(3, 7) ); System.out.println( test.div(16, 4) ); System.out.println("-----Test isSum24()------------"); int a[] = {6, 3, 8, 3, 4}; int b[] = {5, 6, 7};int c[] = {24}; int d[] = {10, 14}; int e[] = {}; System.out.println( test.isSum24(a) ); System.out.println( test.isSum24(b) ); System.out.println( test.isSum24(c) ); System.out.println( test.isSum24(d) ); System.out.println( test.isSum24(e) ); System.out.println("-----Test reverseArray()------------"); test.reverseArray(a); System.out.println(Arrays.toString(a)); test.reverseArray(b); System.out.println(Arrays.toString(b)); test.reverseArray(d); System.out.println(Arrays.toString(d)); System.out.println("-----Test recursiveSelectionSort()------------"); test.recursiveSelectionSort(a, 0, a.length - 1); System.out.println(Arrays.toString(a)); int f[] = {2, 5, 1, 7, 9, 3, 6, 8};test.recursiveSelectionSort(f, 0, f.length - 1); System.out.println(Arrays.toString(f));//12356789}}

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access with AI-Powered Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Students also viewed these Databases questions