I understand how they found the M (concentration), but how did they convert m/l to g/l.

Can someone please break it down, and explain how the conversion is done for future questions.

Consider the dissolution of calcium sulfate, CaSO4, given that its Ksp is 2.4105. (i) Write a balanced equation for the dissolution of calcium sulfate and calculate its molar solubility in g/L. CaSO4(s)=Ca2+(aq)+SO42(aq)Ksp=[Ca2+][SO42]2.4105=s.ss=4.9103M The molar solubility of CaSO4 in g/L=4.9103mol/LMM(CaSO4) =4.9103mol/L(40.078+(32.06+(15.999)4)g/mol=0.67g/L