I want to know yellow boxes.

Traffic Count he British Department of Transportation studied to see if people avoid driving on Date 6th 13th According to the February 2008 Federal Trade Commission report on consumer fraud and identity theft, 20% of all complaints in 2007 were for identity theft. In that year, Alaska had Friday the 13th. They did a traffic count on a Friday the 6th and then again on Friday 7-90 139246 138548 300 complaints of identity theft out of 1,600 consumer complaints. Does this data provide the 13th at the same 2 locations. The data for each location on the 2 different dates is 7-90 POINTS Out OF 134012 132908 enough evidence to show that Alaska had a lower proportion of identy theft than 20%? given below to the right. Does the data show an average few Pople drive on Friday the POINTS Out OF 9-91 137055 136018 12 13th? Test at a 10% level. 15 9-91 133732 131843 12-91 123552 121641 Ho 12-91 121139 118723 H . : 3-92 128293 125532 a = 3-92 124631 120249 Sample Statistic Ho: 11-92 SE = H . : 124609 122770 Test Statistic PV= 11-92 117584 117263 a = dec Sample Statistic SE = Test Statistic PV = dec % PV = ? PV = ? Conclusion about null hypothesis Conclusion about null hypothesis Interpret you alternative hypothesis Interpret you alternative hypothesis POINTS Out OF Calculate a 95% confidence interval for the proportion if identity thefts in Alaska. 10 PE Critical Value ompute a 90% confidence interval for mean difference in traffic count between the 6th POINTS Out OF SE = and 13th. ME = 10 Upper Lower PE= CONFIDIENCE INTERVAL Critical Value SE = ME = Upper Point Estimator + Marigin of Error Lower CALCULATE CONFIDIENCE INTERVAL Interval Point Estimator : Marigin of Error Interval STATISTICAL INTERPRETATION STATISTICAL INTERPRETATION REAL WORLD INTERPRETATION REAL WORLD INTERPRETATION