I would like some assistance with the following probability distrution sampling distribution and inference for mean and population exercise

I would like detailed explanation as well

A census of male university graduates showed that 70% would date a woman who does not have a university degree. What is the probability that in a sample of 280 male university graduates, 75% or more would date a woman who does not have a university degree? Select one: O a. 0.9732 O b. 0.0336 O c. 0.9664 O d. 0.0268The writer of the Dear Dr column wanted to know "If you could do it all over again, would you get married?". The Gleaner randomly contacted 1000 subscribers from 5 age groups. Five hundred responded saying no. This is an example of Select one: a. Voluntary sampling O b. Multi-Stage sampling c. Simple random sampling d. Stratified sampling e. Cluster sampling.For a sample of 36 cars, the length of time it takes to change a muffler is 37.9 minutes. If the standard deviation of time spent conducting business is known to be 20 minutes, the upper limit for a 90% confidence interval is Select one: O a. -32.417 O b. 43.383. O C. 31.367. O d. 44.433. O e. -38.974.If the null hypothesis is rejected at the 10% level of significance, it Select one: O a. will be rejected at the 5% level of significance O b. will be not be rejected at the 5% level of significance. O c. may or may not be rejected at the 1% level of significance. d. will be rejected at the 1% level of significance. O e. will be rejected at the 20% level of significanceThe distribution of the estimates of regular maintenance on a specific vehicle is left skewed with a mean of $3000 and a standard deviation of $1000. The distribution of the sample mean for a sample of 100 cars is Select one: O a. Normal with mean $3000 and standard deviation $100. O b. Normal with mean $3000 and standard deviation $1000. O c. Left skewed with mean $3000 and standard deviation $1000. O d. Left skewed with mean $3000 and standard deviation $100. e. Right skewed with mean $3000 and standard deviation $100